Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Which polynomial represents the sum below? (-2x^3 + 4x^2 + 6) + (2x^2 + 6x + 3) A. -x^6 + 6x^2 + 12x + 9 B. -2x^3 + 6x^2 + 6x + 9 C. -2x^5 + 10x^2 + 6x + 9 D. -2x^3 + 6x + 9

OpenStudy (anonymous):

Your answer should be B if you put all the common parts together you will find you can not simplify the equation any longer

OpenStudy (anonymous):

thank you so much

OpenStudy (anonymous):

No problem do you understand it?

OpenStudy (anonymous):

yes i do now thank u

OpenStudy (anonymous):

Which polynomial represents the sum below? (2x^6 + 3x^2 + 9) + (3x^2 + x + 8) this is the answer i got 5x^8 + 3x^4 + x + 17 did i do it right

OpenStudy (anonymous):

mmbuckaroos did i do this right ?

OpenStudy (anonymous):

Ha ha let me check sorry I was working on something else...

OpenStudy (anonymous):

ok no problem

OpenStudy (anonymous):

No that's not right....Here I will go through the problem step by step

OpenStudy (anonymous):

(2x^6 + 3x^2 + 9) + (3x^2 + x + 8) ok between both the sides what do you see in common?

OpenStudy (anonymous):

3x^2

OpenStudy (anonymous):

Right... so because there is nothing in common with 2x^6 I leave that then I would add the two common parts together so add 3x^2+3x^2 together and you should get 6x^2

OpenStudy (anonymous):

Then there are no other x's so you leave the x alone. then add the 9&8 together and you should get 17.

OpenStudy (anonymous):

ok yea now im getting it

OpenStudy (anonymous):

Your final answer should be 2x^6+6x^2+x+17

OpenStudy (anonymous):

Does that make sense i didn't do the best job explaining it sorry

OpenStudy (anonymous):

yes it does now that u explained ill try another one and get back to u

OpenStudy (anonymous):

Alright sounds like a plan Stan! Lol I'd trade that math for mine any day! lol

OpenStudy (anonymous):

lol :)

OpenStudy (anonymous):

6x^7+9x^3-x+9 + 2x^7+7x^6+6 this is the answer i got is it right 8x^7+7x^6+9x^3-x+15

OpenStudy (anonymous):

how is this one mmbuckaroos

OpenStudy (anonymous):

ok so what is your original equation again sorry is it: 6x^7+9x^3-x+9+2x^7+7x^6+6

OpenStudy (anonymous):

yes and the answer i got is 8x^7+7x^6+9x^3-x+15 is it right

OpenStudy (anonymous):

Yes sir! you got it good job!

OpenStudy (anonymous):

well thank you im proud lol :)

OpenStudy (anonymous):

Ha ha good you should be!

OpenStudy (anonymous):

Which polynomial represents the sum below? (4x^2 + 3x + 4) + (-3x^6 - 4x^5 - 2x^2 + 5x) ok the answer i got is -x6 - 4x5 + 2x2 + 8x + 4

OpenStudy (anonymous):

close look over it again.. I think you meant -3x^6

OpenStudy (anonymous):

oh ok sorry yea i looked it over

OpenStudy (anonymous):

Other than that you've got this down!

OpenStudy (anonymous):

Good job!

OpenStudy (anonymous):

Which polynomial represents the sum below? (18x^2 - 18) + (-13x^2 - 13x + 13) ok well the answer i got is 5x2 - 13x - 5

OpenStudy (anonymous):

5x^2 - 13x - 5

OpenStudy (anonymous):

i ment that

OpenStudy (anonymous):

Yeppers! You're on a role!

OpenStudy (anonymous):

wow thx u oh yea:)

OpenStudy (anonymous):

Ha ha no problem!

OpenStudy (anonymous):

7x^8 +5x^5 - x+8 + 5X^10 +9X+8 the answer i got is 12x16 + 4x4 + 7x + 16

OpenStudy (anonymous):

No...make sure you have the correct original problem

OpenStudy (anonymous):

If you do your highest power should be 5x^10 and there is nothing in common with that

OpenStudy (anonymous):

5x10 + 7x8 + 5x5 + 8x + 16 is this the answer

OpenStudy (anonymous):

yep!

OpenStudy (anonymous):

sweet :)

OpenStudy (anonymous):

Good job!

OpenStudy (anonymous):

(x^6 + x ) + (8x^6 + 4) the answer i got for this one it 9x^6+5

OpenStudy (anonymous):

I have to go get a horse trimmed, but if you have anymore questions I'll be back to answer them in a while

OpenStudy (anonymous):

ok thank you very much for your help :)

OpenStudy (anonymous):

alright sorry about that... Your last problem would be 9x^6 +x+4

OpenStudy (anonymous):

im here

OpenStudy (anonymous):

do oyu see where you made your mistake on that last one?

OpenStudy (anonymous):

*you

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

cool beans!

OpenStudy (anonymous):

2x^5 -3x^3 + x^2 +4 + -3x^5 -2x^4 +x^3 +4x the answer i got is -1x^5 + 5x^6 + 2x^5 8x+-1

OpenStudy (anonymous):

what do you think buck

OpenStudy (anonymous):

close -x^5-2x^4-2x^3+x^2+4x+4

OpenStudy (anonymous):

(5x4 - 3x2 - 2x) + (2x4 + 2x3 + 2x2 + x + 1) i really cant get this one

OpenStudy (anonymous):

(5x^4 - 3x^2 - 2x) + (2x^4 + 2x^3 + 2x^2 + x + 1)

OpenStudy (anonymous):

this is the right one

OpenStudy (anonymous):

ok give me a sec

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

what is your answer

OpenStudy (anonymous):

i couldnt get the answer for this one

OpenStudy (anonymous):

ok... what do you see in common

OpenStudy (anonymous):

3x^2 2x^3

OpenStudy (anonymous):

mm not quite... ok so what's the highest power and is there anything similar to it

OpenStudy (anonymous):

4 is the highest power

OpenStudy (anonymous):

so what is in common with 5x^4

OpenStudy (anonymous):

2x^4

OpenStudy (anonymous):

right so add those together to get 7x^4 then do you see anything in common with 2x^3?

OpenStudy (anonymous):

yea 3x^2

OpenStudy (anonymous):

No because they have a different power... only alike powers can be put together.. Comprende?

OpenStudy (anonymous):

sorry getting tired lol

OpenStudy (anonymous):

2x^2

OpenStudy (anonymous):

so 2x^3 should be by itself... ha ha it's ok and 2x^2 add that to -3x^2 because they share the same power.. are you following ?

OpenStudy (anonymous):

yup so what next

OpenStudy (anonymous):

you should get -x^2... Next, you have the x's with out powers in common (x & -2x) so you should put those together to get -x.

OpenStudy (anonymous):

Then the 1 is all by it's lonesome self. Your answer should be: 7x^4+2x^3-x^2-x+1

OpenStudy (anonymous):

thank you so much for all your help im leaveing im am tired

OpenStudy (anonymous):

ha ha no problem anytime get some rest math wiz!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!