The terminal speed (in m/s) of the skydriver can be approximated by square root 40 m, where m is the mass (in kg) of the skydiver. calculate the terminal speed of a 100-kg shydiver. write an exact answer in radical form. simplify the radical by factoring.

Question

The terminal speed (in m/s) of the skydriver can be approximated by square root 40 m, where m is the mass (in kg) of the skydiver.  calculate the terminal speed of a 100-kg shydiver. write an exact answer in radical form.  simplify the radical by factoring.

bahrom7893 · Answer

Okay let's try to solve this in simple steps.

bahrom7893 · Answer

Terminal velocity equation:
$$V_t = \sqrt((2mg)/(\rho*A*C_d))$$

bahrom7893 · Answer

(everything is under square root)

bahrom7893 · Answer

where:
$$V_t$$ is  terminal velocity
m is mass of the falling object
g is acceleration due to gravity (9.81m/s^2)
Cd = drag coefficient
ρ = density of the fluid through which the object is falling
A = projected area of the object.

bahrom7893 · Answer

In your case, the terminal Velocity is $$\sqrt{40*m}$$ where m is the mass (in kg) of a skydiver.

bahrom7893 · Answer

So if you need the terminal velocity of a skydiver whose mass is 100kg, then plug in 100kg into the equation above... You didn't even need the terminal velocity equation and all that crap.. sorry I didn't read the question carefully first time

bahrom7893 · Answer

In your case, the terminal Velocity is $$\sqrt{40*m}$$ where m is the mass (in kg) of a skydiver. If the skydiver's mass is 100kg, then the terminal velocity is:
sqrt( 40 * 100 ) = sqrt(400 * 10) = 20sqrt(10)

bahrom7893 · Answer

The answer is 20 * sqrt(10) m/s

anonymous · Answer

wow that helped alot thanks