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Mathematics 16 Online
OpenStudy (wolf):

A certain forest covers an area of 2400km^2. Suppose that each year this area decreases by 8.5%. What will the area be after 13 years?

OpenStudy (anonymous):

This is like the equation of a line where y is the area, x is the time, and 8.5% is your slope. So you have y=0.085x+b (reason why I switched 8.5% into 0.085 is because that is how you write a percent as a decimal). So now you need to find what b is. So you know orignally the area is 2400km^2 at x=0 years (this is what it is initially). If you plug those numbers in you have: 2400=0.085(0)+b Then after solving for b, you can write your equation as: y=0.085x+(whatever you found b to be) Then plug 13 in for x and you have your answer.

OpenStudy (wolf):

So I am solving for y? and my slope is negative right?

OpenStudy (anonymous):

ooops, you're right it is negative.

OpenStudy (wolf):

so i'm doing y=-.085(13)+2400?

OpenStudy (anonymous):

Yep; exactly.

OpenStudy (wolf):

but if i round to the nearest kilometer I get 2399? is that right? I mean the first yea almost 10 percent of the forest should be gone

OpenStudy (anonymous):

Ah, I oversimplifying the problem! So the equation you have to use is actually A(t)=2400*(1-0.085)^t

OpenStudy (wolf):

i did something different now I get 2386

OpenStudy (wolf):

ok so 756

OpenStudy (wolf):

that sounds a lot better haha

OpenStudy (anonymous):

Mhm. Sorry I have been helping some other people with linear problems so my brain is set on that right now for some reason.

OpenStudy (wolf):

Thank you

OpenStudy (anonymous):

You're welcome.

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