A certain forest covers an area of 2400km^2. Suppose that each year this area decreases by 8.5%. What will the area be after 13 years?
This is like the equation of a line where y is the area, x is the time, and 8.5% is your slope. So you have y=0.085x+b (reason why I switched 8.5% into 0.085 is because that is how you write a percent as a decimal). So now you need to find what b is. So you know orignally the area is 2400km^2 at x=0 years (this is what it is initially). If you plug those numbers in you have: 2400=0.085(0)+b Then after solving for b, you can write your equation as: y=0.085x+(whatever you found b to be) Then plug 13 in for x and you have your answer.
So I am solving for y? and my slope is negative right?
ooops, you're right it is negative.
so i'm doing y=-.085(13)+2400?
Yep; exactly.
but if i round to the nearest kilometer I get 2399? is that right? I mean the first yea almost 10 percent of the forest should be gone
Ah, I oversimplifying the problem! So the equation you have to use is actually A(t)=2400*(1-0.085)^t
i did something different now I get 2386
ok so 756
that sounds a lot better haha
Mhm. Sorry I have been helping some other people with linear problems so my brain is set on that right now for some reason.
Thank you
You're welcome.
Join our real-time social learning platform and learn together with your friends!