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Find the linear approximation L (x) of the function F(x)=x^6+3x^2 at a=-1....L(x)=A+Bx where A=? and B=?
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L = f(a) + f'(a)(x-a)... L = x^6 + 3x^2 + (6x^5 + 6x)(x-a)... L = (-1)^6 + 3(-1)^2 + (6(-1)^5 +6(-1))(x-(-1))... L = 4 + (-12)(x+1)... L = 4 -12x -12... L = -8-12x...
so how do u figure out what a and b equal
Well wasn't it given: L = A + Bx quantish above solved: L = -8 - 12x L = A + Bx A = -8; B = -12
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