Question

find 3rd derivate x/x+1

Answer 1

Okay now jjanelle, see what I meant, i doubt this problem meant x/x + 1, or it would just be 2... That's why I like to keep parenthesis all the time..

Answer 2

I would solve it like this:
\[y=x*(x+1)^{-1}\]

Answer 3

and use the product and chain rules..

Answer 4

\[y' = x(-1)(x+1)^{-2} + (x+1)^{-1}*1\]

Answer 5

\[6/(x+1)^{4}\]

Answer 6

\[y' = (x+1)^{-1} - x(x+1)^{-2}\]

Answer 7

\[y'' = - (x+1) - [x(-2)(x+1)^{-3} + (x+1)^{-2}]\]

Answer 8

\[y" = -x - 1 +2x(x+1)^{-3} - (x+1)^{-2}\]

Answer 9

\[y''' = -1 + 2x(-3)(x+1)^{-4} + (x+1)^{-3}*2 + 2(x+1)^{-3}\]

Answer 10

\[y''' = -1 -6x/(x+1) + 2/(x+1)^3 + 2/(x+1)^3\]

Answer 11

\[y''' = -1 -6x/(x+1) + 4/(x+1)^3\]

Answer 12

thank you