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Mathematics 7 Online
OpenStudy (anonymous):

The accompanying table shows the scores on a classroom test. What is the population standard deviation x: 100, 95, 90, 80, 75, 72, 70 f: 7, 2, 10, 4, 2, 3, 4

OpenStudy (anonymous):

ooh statistics.....dont remember this but tiere's a formula for Standard Deviation...google it lol

OpenStudy (anonymous):

f stands for frequency, so that's the number of x' of that particular value that occurred. So x = 100 occurred 7 times in the population. x = 95 occurred twice. And so on. Find the mean of your population is the first step. That means summing over all the scores of the class and dividing by the class size.

OpenStudy (anonymous):

\[\sum_{n=1}^{3}i^(n-1)\]

OpenStudy (anonymous):

that should read i^(n-1)

OpenStudy (anonymous):

what's that?

OpenStudy (anonymous):

sum?

OpenStudy (anonymous):

What is that sum for formula for?

OpenStudy (anonymous):

the top part means you do the formula on the right 3 times using n=1 n=2 n=3 and then add up all those values

OpenStudy (anonymous):

but the i is raised to the n-1

OpenStudy (anonymous):

What's the formula represent? Is this a different problem? I thought you were asking about standard deviation.

OpenStudy (anonymous):

yeah its a different problem i figured out the other one ill use my calculator

OpenStudy (anonymous):

So what's the sum asking you to do? You want to find an explicit formula for the sum?

OpenStudy (anonymous):

no you need to find the sum of all those terms

OpenStudy (anonymous):

I have a feeling you wrote the problem wrong. As it is, it makes no sense. Unless the teacher just wants you to write: i^(0) + i^(1) + i^(2). That's the sum.

OpenStudy (anonymous):

yeah u do i^1+i^2+i^3 and add them up

OpenStudy (anonymous):

you start with 1 because thats what n=

OpenStudy (anonymous):

You raise it to (n-1). So when n = 1, n-1 is 0. So the first power is 0. The next power increased by 1, so it's 1.

OpenStudy (anonymous):

nev ermind its fine..can you look at my probability question

OpenStudy (anonymous):

no i gotta go

OpenStudy (anonymous):

if you post it on here, someone will be sure to help. there's a lot of people on right now

OpenStudy (anonymous):

okk

OpenStudy (anonymous):

good luck

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