Question

Let f be the function with derivative given by f'(x)=x^2 - 2/x.Determine tje intervals on which f is decreasing.

Answer 1

find where f'(x) = 0.
x² - 2/x = 0
x = 3sqrt(2)
now plug in 2 values - greater than and less than 3sqrt(2)
which ever is negative, is the decreasing one.

Answer 2

x = 0 is also a critical number.

Answer 3

O.o howd you get 0?

Answer 4

banshee -2/x

Answer 5

u need where the function doesn't exist too...

Answer 6

oh rightttt
doesnt exist xD touche!

Answer 7

lol review ur calc...

Answer 8

; )

Answer 9

Now im confuse somthing dnt add up