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OpenStudy (anonymous):
\[3t*((\sin t)/(t- t ^{2/3}))\]
Is this the question?
OpenStudy (anonymous):
i need to find the derivate
OpenStudy (anonymous):
I know, I want to know if I wrote the question correctly.
OpenStudy (anonymous):
yes :=)
OpenStudy (anonymous):
Okay. Its quite trivial, but tedious. Its easy to make mistakes in this. Do you just want the answer to verify your answer or do you need explanation also?
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OpenStudy (anonymous):
yes i want the answer please i want to verify if with mine these derivates are driving me crazy
OpenStudy (anonymous):
wait the question is wrong
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
3t((sint/t)-t^2/3))
OpenStudy (anonymous):
3T(sin t divided by t and t^2 divided by 3)
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OpenStudy (anonymous):
aite cool
OpenStudy (anonymous):
Well. This problem looks alot less tedious than before.
Just distribute the 3t and you'll get:
3sin(t) - t^3
When you take its derivative you'll get:
3cos(t) - 3t^2
OpenStudy (anonymous):
i got 3cos(T)-9T^2 the 9 from multiplying 3t(t^2/3) dont know ;-(