how do i find the anti derivative of 9-4x^2 all raised to 1/2
first raise everything to the (1/2) power. 9^(1/2) - 4^(1/2)(x^2)^(1/2) and get 3 - 2x.
apparently i need to use the table of integrals and it says perhaps one substitutions
ok would that be finding the perfect square?
yeah theyre all perfect squares. its easy to get the anti derivative now
how do i do it with table of integrals?
the table is just all the rules for finding the anti derivative aka integral
\[\sqrt{9-4x^2}\] fits into square root of a^2 +or- x^2 but laves 1 over the square root of a^2-x^2 to still be found
i cant get it to fit into any other equation
sorry i wasnt looking at it right http://www.wolframalpha.com/input/?i=integral+%289-4x^2%29^%281%2F2%29
copy the whole thing dont click
k
how do i tell what equations it used though?
ok i see thank you so much!!!!!!!!!
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