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Mathematics 7 Online
OpenStudy (anonymous):

whats the integral of lnt/t

OpenStudy (anonymous):

You can solve this using u-substitution. let u = Ln(t) so du = 1/t dt

OpenStudy (anonymous):

The problem then becomes \[\int\limits_{?}^{?}u du = u ^{2}/2 + c = (Ln(t))^{2}/2 + c\]

OpenStudy (anonymous):

\[\int\limits_{1}^{e}\]

OpenStudy (anonymous):

You need the integral from 1 to e?

OpenStudy (anonymous):

yes evalute

OpenStudy (anonymous):

you should try it from here

OpenStudy (anonymous):

ok.. thanks

OpenStudy (anonymous):

Ln(1)^2 - Ln(e)^2

OpenStudy (anonymous):

oops, sorry. Ln(e)^2-Ln(1)^2

OpenStudy (anonymous):

then divide the answer by 2

OpenStudy (anonymous):

ln|1| is 0 right

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the answer is 1/2

OpenStudy (anonymous):

you got it :)

OpenStudy (anonymous):

thanks a lot

OpenStudy (anonymous):

one more. I seem to have trouble converting radicals to exponentials

OpenStudy (anonymous):

trying to figure out the integral of dt/3 root of t

OpenStudy (anonymous):

I meant cube root of t

OpenStudy (anonymous):

let me write it out \[dt/\sqrt[3]{t}\]

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