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whats the integral of lnt/t
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You can solve this using u-substitution. let u = Ln(t) so du = 1/t dt
The problem then becomes \[\int\limits_{?}^{?}u du = u ^{2}/2 + c = (Ln(t))^{2}/2 + c\]
\[\int\limits_{1}^{e}\]
You need the integral from 1 to e?
yes evalute
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you should try it from here
ok.. thanks
Ln(1)^2 - Ln(e)^2
oops, sorry. Ln(e)^2-Ln(1)^2
then divide the answer by 2
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ln|1| is 0 right
yes
the answer is 1/2
you got it :)
thanks a lot
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one more. I seem to have trouble converting radicals to exponentials
trying to figure out the integral of dt/3 root of t
I meant cube root of t
let me write it out \[dt/\sqrt[3]{t}\]
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