Question

indefinite integral of (2/cubed root of x) - 3 cubed root of x^2

Answer 1

3/2*x^(4/3)-9/5*x^(5/3)+C using the power rule for integrals.

Answer 2

I need some clarification on converting radical in denominator to numerator in exponential form

Answer 3

I always get confused.
so if you could list a few of them and show me I will be able to apply the power rule for intgrals
thanks

Answer 4

Ok I think I might have got it...except the 9/5 how did you get that?

Answer 5

shouldn't it be 3/5 * x ^ (5/3)?

Answer 6

Hold on. We're trying to integrate 2*x^(-1/3)-3*x^(2/3). So... using integral rule, 2*1/(1-1/3)*x^(2/3)-3*1/(1+2/3)*x^(5/3)= 3x^(2/3)-9/5*x^(5/3)

Answer 7

+C. I did make a mistake initially.

Answer 8

\[2/ \sqrt[3]{x} - \sqrt[3]{x^2}\]

Answer 9

this is my question

Answer 10

Yes. I know that. Haha.

Answer 11

3x^(2/3)-3/5*x^(5/3)+C. Your 3 threw me off.

Answer 12

sorry about that.. now it totally makes sense, thanks

Answer 13

Fan me then. :D

Answer 14

can I do one and you check and see if still understand

Answer 15

\[dt/\sqrt[3]{t}\]

Answer 16

so i get 3/2* t^2/3 +c

Answer 17

Yup. :)

Answer 18

i also get confused about ln|x| stuff

Answer 19

example (2x^4 - x)/ x^3 dx = I get x^2 +x^-1 +c

Answer 20

Ask a new question about this preferably. I don't wanna clutter one question up.

Answer 21

ok I just want to know why can't I write ln|x| for x^-1

Answer 22

You should be able to?

Answer 23

The integral of x^-1 is ln|x|+C

Answer 24

ok.. that's all I want to know.. it's sometimes text book shows one way and the other time it shows ln |x| without any explanation

Answer 25

I am good on this one now
thanks again

Answer 26

It should be ln|x| because you can't take a log of a negative number.