Question

find derivate of - 3/ x^3

Answer 1

is this +9/ X^4

Answer 2

quotient rule= (x^3)(-3)'-(x^3)'(-3) all over x^6 so this = (x^3)(0)-(3x^2)(-3) all over x^6

Answer 3

the problem i get from my book is find derivate f(x)=3X^3 - (8X^3/4 DIVIDED 3) - (3 / x^3

Answer 4

SO MY ANSWER IS 9X^2 - 2X^-1/4 + 9X^-4 IS THIS CORRECT

Answer 5

-9x^2

Answer 6

but you just pulled a part from the question, thats why i solved only for that derivative because its still -9x^2/x^6

Answer 7

or 9/x^4 so yea you are right 9x^-4

Answer 8

but that should still be -9x^-4

Answer 9

OK SO THE 3RD TERM IS NEGATIVE THANK YOU

Answer 10

is the problem -(3/x^3) or -3/x^3

Answer 11

itll be positive if it becomes -(-9x^-4)=9x^-4 if there isnt a negative, it will stay -9x^-4

Answer 12

-(3/x^3) THE PROBLEM

Answer 13

then its negative

Answer 14

because its 9x^2/x^6=9/x^4=9x^-4 then -(9x^-4)=-9x^-4

Answer 15

OK THANKS I JUST THOUGHT THAT BECAUSE X^3 DE DENOMINATOR IF I BRING IT UP IT WILL BE -(3X^-3) SO THEN IT WILL BE POSITIVE

Answer 16

its fine, you just have to do the quotient rule, and then at the end associate the negative with the derivative you found for the section