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derite of 2 / sqareroot of T^3 is this 2t^-1/3
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2/(squareroot (t^3)) = 2/(t^(3/2) = 2t^(-3/2) Taking the square root is the same as raising to the 1/2 power.
OK I THOUGT FOR SOME REASON IT WAS 2T^-1/3
are you asking for the derivative?
because then its -3/2(2t)^-5/2
which is is -3t^-5/2
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YES DERIVATE OF 2 DIVIDED SQTROOT OF T^3
(d/dt) [2t^(-3/2)] = -3t^(-5/2) Just rewrite with a negative exponent and use the power rule. Alternatively, you could use the quotient rule, but this is the easiest way when you don't have any exponents in the numerator.
*variables, not exponents
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