Mathematics
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OpenStudy (anonymous):
solve: y^2/3=64
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OpenStudy (anonymous):
y=64^(3/2)=8^3
OpenStudy (anonymous):
y= 16?
OpenStudy (anonymous):
but the choices are +512 or +16 or 16 or 512 the last two are listed without positvie sign but dont have a neg either
OpenStudy (anonymous):
Well, -8^3 works as well. 8^3 is 512, by the way.
OpenStudy (anonymous):
Is your question y^2*1/3=64 or y^(2/3)=64?
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OpenStudy (anonymous):
so would i chose +512 or just 512
OpenStudy (anonymous):
I don't think there's a difference unfortunately.
OpenStudy (anonymous):
its y^(2/3)=62
OpenStudy (anonymous):
y = \[y=\sqrt([3]{63}) then ^2 \it\], i agree no plus or minus,
OpenStudy (anonymous):
Well, the answer is 512 or -512. Either one works.
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OpenStudy (anonymous):
i mean 64
OpenStudy (anonymous):
but mirwiz has right answer and order of operation
OpenStudy (anonymous):
so i figure im ganna go with just 512
OpenStudy (anonymous):
Yeah... I guess so. That's stupid. 512 is the same as +512.
OpenStudy (anonymous):
i know idk y its a choice
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OpenStudy (anonymous):
i also had another similar question z^(3/2) = 64
OpenStudy (anonymous):
It's the same thing as (z^(1/2))^3=64.
z^(1/2)=64^(1/3)=4
z=16. -16 is not a solution here because you can sqrt a negative number.
OpenStudy (anonymous):
wut bout (w+1)^(3/2)=64
OpenStudy (anonymous):
The same thing, except you subtract 1.
OpenStudy (anonymous):
from 64?