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Mathematics 6 Online
OpenStudy (anonymous):

for h(x)=x^2-2x+7, compute, lim h(x)-h(1)/x-1 when x approach to 1

OpenStudy (anonymous):

so...compute lim as x -->1 for ??? is that [h(x) - h(1)]/(x-1)?

OpenStudy (anonymous):

\[\lim_{x \rightarrow 1} (x^2-2x+1)/(x-1) = \lim_{x \rightarrow 1} ((x-1)(x-1))/(x-1)\] so, after factoring, and simplifying, you're left with...

OpenStudy (anonymous):

lim x-->1 (x-1) = 0

OpenStudy (anonymous):

what happened with 7?

OpenStudy (anonymous):

h(x) = x^2-2x+7 h(1) = (1)^2-2(1)+7 = 6 h(x) - h(1) = x^-2x+7-6 = x^2-2x+1

OpenStudy (anonymous):

cool

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