Oil is leaking from a tanker at the rate of R(t) = 2000e^(-0.2t) gallons per hour where t is measured in hours. How much oil leaks out of the tanker from the time t = 0 to t = 10
For background knowledge, what math are you in?
AP Calculus
Okay, that's what I thought. So you know integrals?
Sort of
Do you know what they're used for?
not really
Well, this is one prime example of what they're used for. If you graphed the equation you said, taking the integral of it would essentially find the area filled in between your line and the x axis
What this means when the line represents a rate is that your x axis will essentially represent time elapsed and the area filled in is the total
Do you get that?
Yeah, I think so! Can I just plug the equation into the calculator to graph it and then get my answer from there?
Not really (unless you know have a TI-89 which can integrate)
I do have one :)
Hahaha. Well if you're allowed to, go for it. Before I say do it to it, how would you set up the integral for this equation?
Also, just thought you should know that sunflowers are my dad's favorite so I approve of the name, haha
\[\int\limits_{0}^{10}2000e^(-.2t)\]
Haha well they're my favorite too X-)
You have to include dt, but yea.
Oops! Ok! Then I get confused though, where do I go from there?
Once you take the integral from 0-10 of a rate equation, you've found the total. What I mean by that is this. Let's say you're going to the beach at a rate of 63 miles per hour from the first hour to the fourth hour
let u be -0.2t, du = -.2dt and integrate...
Yeaaah.... You lost me. I don't understand how to take the integral, the fact that theres an e there messes me up.
I thought you just put the integral into your calculator. That should be your answer.
I was just about to explain why that's the answer.
That seems too easy though, aren't there more steps or something?
That's it, gimme a sec to explain.
Ook X-)
Like I was saying, I drive at 63 miles/hour from the first hour to the fourth (not including). I want the total number of miles driven. Using an integral to do this, I set it up like this:
\[\int\limits_{1}^{4} (63 miles/hour)dhour\]
The 1 and 4 are points 1 and 4 on the hour axis (x axis in your calculator)
Integrating with respect to dhour essentially gets rid of the /hour and returns just the total number of miles driven.
Go ahead and test it to make sure.
That integral should return the same number as if you just did the simple multiplying of 3 hours by the 63 miles/hour
While it's seemingly more work to do it with something simple like my example, it translates exactly the same way as in your example.
Ok! I think that makes sense! Can you check my answer to my problem though? I'm getting 8647 gallons when I use the calculator.
If you're given a rate with a time variable, you just take an integral that starts at the first point and ends at the last point and integrate the rate with respect to the time variable, in this case t.
Okay, lemme load it up
8646.65
Close enough :) I don't know why expected that to be so much more complicated, thank you!
Yea, it's not that bad when you understand what integrals really do.
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