Question

i do not know how to do this.
one base of a trapezoid is twice as long as the other. the height is the average of the 2 bases. the area is 324 cm squared. find the height and lengths of the bases.

Answer 1

A=(h(b1+b2))/2
b1=x, b2=2s, h=b1+b2=3x
324=(3x(2x+x))/2
324=9x/2
(324 x 2)/9=x
x=72,subtitution find base, height
base 1=72 , base 2= 144, height=216
check: (216 x (72+144))/2= (216 x216)/2

A=324

Answer 2

A=(h(b1+b2))/2
b1=x, b2=2s, h=b1+b2=3x
324=(3x(2x+x))/2
324=9x/2
(324 x 2)/9=x
x=72,subtitution find base, height
base 1=72 , base 2= 144, height=216
check: (216 x (72+144))/2= (216 x216)/2

A=324

Answer 3

A=(h(b1+b2))/2
b1=x, b2=2s, h=b1+b2=3x
324=(3x(2x+x))/2
324=9x/2
(324 x 2)/9=x
x=72,subtitution find base, height
base 1=72 , base 2= 144, height=216
check: (216 x (72+144))/2= (216 x216)/2

A=324

Answer 4

A=(h(b1+b2))/2
b1=x, b2=2s, h=b1+b2=3x
324=(3x(2x+x))/2
324=9x/2
(324 x 2)/9=x
x=72,subtitution find base, height
base 1=72 , base 2= 144, height=216
check: (216 x (72+144))/2= (216 x216)/2

A=324