Question

How can I solve this indefinite integral without having arcsin in the result?
\int \sqrt{1-x^2} dx Thanks!

Answer 1

The integral is this: \[\int\limits \sqrt{1-x^2} dx\]

Answer 2

i dont see how you got arcsin?

/int for arsin is 1/(a^2 -x^2)^.5

Answer 3

\[1/\sqrt{(a^2 - x^2)}\]

Answer 4

I solved it with this substitution x=sin(t)
result: 1/2arcsin(x)+1/4sin(2arcsin(x))

Answer 5

I LOL YOU