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Mathematics 68 Online
OpenStudy (anonymous):

How do I find the derivative of cos^2(x)

OpenStudy (anonymous):

use the chain rule. that function is the composition of cos(x) and x^2

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

\[y=\cos^2x\] \[y'=2(cosx)^1\] \[y'=2cosx\]

OpenStudy (anonymous):

-1 fan for corec

OpenStudy (anonymous):

\[y′=2(cosx)1(cosx)'\] \[y′=2 cosx sinx\]

OpenStudy (anonymous):

-2 (both fans for corec and the constant in front of his answer)

OpenStudy (anonymous):

right =) y' = -2 cosx sinx lol

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