Question

Determine the equation of the line tangent to the graph of the following function at x = 0.
g(x) = ex(−4 + 3x + 3x2)

Answer 1

the eqn is y+4-6x^2-3x

Answer 2

y+4-6x^2-3x = 0 ***

Answer 3

how did you figure that one man?

Answer 4

first you the y-value when x=0(so y=-4) and then when you find the equation of the tangent at any piont (aka, the slope) you use the slope, and your x and y value and sub them into the y=mx+b eqn to get it
or you can use slope=(-4-y)/(o-x)

Answer 5

only one problem. we're looking for the equation of a straight line. so it couldn't have any squared values in it

Answer 6

true,
okay the answer is
y=3x+4

Answer 7

that was considered the wrong answer when i submitted

Answer 8

what grade are you in?

Answer 9

im a senior in high school

Answer 10

okay, and what's the ex in front of the eqn?

Answer 11

g(x) = e^x(−4 + 3x + 3x^2)

Answer 12

e to the power of x?

Answer 13

yezzir

Answer 14

whoa thats wierd, i didnt even consider that

Answer 15

just get the derivative using product rule, then sub 0 in for x and find the slope at that point, and then use y=mx+b, no big.

Answer 16

a'ight could you check my answer for me after i work it?

Answer 17

k go, young grasshopper

Answer 18

is there answers in the back of your text book or something?