Question

integral x/(x-2)dx
i know u=x-2, making du=dx
i tried rewriting as u+2/u but got nowhere.

Answer 1

Hmm, would this work?
\[f(x) = x*u^{-1}\]

Answer 2

u can't do that Moss's brother..andrew u were tryin the right approach, i think u made a mistake somewhere:
(u+2)/u = u/u + 2/u = 1 + 2/u
Now if u integrate that,
u + 2Ln|u|, plug in u=x-2
x-2+2 Ln|x-2| <= Your answer..

Answer 3

Or x - 2 +Ln(x-2)^2+C (no need for absolute value as ^2 is always positive, and I forgot the C earlier) Please click on become a fan if I helped! Thanks!