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Mathematics 18 Online
OpenStudy (anonymous):

A prize wheen with a equal sectors numbered from 0 to 36 is spun 400 times. A prime number is the outcome 125 times. a) what is the theoreticcal probability of spinning a prime number? b) In 400 spins, how many times would you expect a prime number to occur ? c) compare your answer to part a) and part b) 4:59 pm

OpenStudy (sandra):

ok so first question is, how many numbers are prime in 0 through 36?

OpenStudy (anonymous):

i dont even know

OpenStudy (sandra):

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

OpenStudy (bahrom7893):

1,2,3,5,7,11,13,17,1..aww u bet me to it lol

OpenStudy (sandra):

haha it's all good :p, took me a while

OpenStudy (anonymous):

1 is not prime

OpenStudy (anonymous):

is it will be 11/ 36?

OpenStudy (sandra):

so if there are 11 prime numbers between 0 and 36, what is the probability of a single spin landing on a prime number?

OpenStudy (sandra):

probability = (possibilities of a prime)/(total number of possibiliies)

OpenStudy (anonymous):

11/36?

OpenStudy (sandra):

close! one problem is 0-36 is actually 37 numbers, since zero counts too :p

OpenStudy (sandra):

so 11/37 is the answer to a

OpenStudy (sandra):

so how do you think you get the answer to b?

OpenStudy (anonymous):

oo waittt

OpenStudy (anonymous):

well

OpenStudy (anonymous):

in 400 spins

OpenStudy (anonymous):

i dont kno

OpenStudy (sandra):

well, if I told you to flip a coin twice, how many times would you expect it lands heads, and how many times tails?

OpenStudy (anonymous):

1 head or 1 tails .. lol

OpenStudy (sandra):

exactly - and the same principle applies here

OpenStudy (sandra):

so the probability of a coin landing heads is 1/2, since there are two sides, and heads is only one of them

OpenStudy (sandra):

so if you flipped it twice, you'd expect 1/2 * 2 heads to show up

OpenStudy (sandra):

so 1 head, and 1 tail

OpenStudy (sandra):

so now if the probability of spinning a prime is 11/37, how many primes would you expect to spin if you spun 400 times?

OpenStudy (sandra):

it's the same thing "probability of it happening once" x "number of attempts"

OpenStudy (sandra):

so 11/37 * 400

OpenStudy (anonymous):

okay i get it

OpenStudy (sandra):

so you would expect 118.92 primes

OpenStudy (anonymous):

484/37

OpenStudy (sandra):

you forgot a zero on the top

OpenStudy (sandra):

11/37 x 400 = (400*11)/37 = 118.92

OpenStudy (sandra):

so you would expect to spin 119 or so prime numbers

OpenStudy (sandra):

that's less than the 125 that were spun in the problem example - but within reason

OpenStudy (sandra):

so part (c) is - that person spun more primes than you'd expect, but not unreasonably so

OpenStudy (anonymous):

how did you even get 118.92?

OpenStudy (sasogeek):

just chipping in if yo don't mind... my msn got messed up. fixed now :)

OpenStudy (sandra):

go for it =)

OpenStudy (anonymous):

ok i get it :)

OpenStudy (sasogeek):

though i can't answer this question now, looks like its already solved but i'll try it on my own :)

OpenStudy (anonymous):

A card is chosen from a deck of cards, recorded, and then replaced. this is done 75 times and red card from 5 to 9 is chosen 21 times. a) what is the theoretical probability of a red card between 5 and 9 being chosen? b) how many times would you expect this event to happen in 75 trials? c) compare your answers to part a) and b)

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