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find the area of the region that is bounded by these equations,, 1) y=lnx, x-axis, x= e^2 2) y = x^2, y = 8-x^, 4x - y +12 =0
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have you done integration yet?
not yer
is calculus class?
yes
Then I think only way to solve it is by using integration. Are you familiar with the concept of integration
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yes
So graph two function in calculator. Which one is on top?
you know how ln(x) curve look like. Also x=e^2 is verticle line.
ln(x) is 0 when x=1 right? so you will \[\int\limits_{1}^{e^2}\ln(x) dx\]
did you get it?
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wait
the answer here in the handout is \[e ^2 +1\]
i got it now... :)
but how can i draw y=lnx and x= e^2 in the cartesian plane
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e^2 verticle line
how can i solve for its x and y coordinate?
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