Question

Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of N 51o W at 14 miles per hour, and the other travels at a bearing of S 56o W at 17 miles per hour. Approximate the distance between them at noon the same day. Round answer to two decimal places.

Answer 1

is it 51 degree north of west

Answer 2

?

Answer 3

A.



20.33 miles


B.



43.25 miles


C.



28.20 miles


D.



22.72 miles


E.



37.19 miles

Answer 4

that doesnt seem reasonable......because it said round your answer to two decimal points. oh answers!

Answer 5

Find x and Y component of speed of each ship

Answer 6

ok so ship a would be 28 miles and shib b would be 34 miles i think

Answer 7

Here How I would solve it ..
Ship 1 travel at 51 degree North of West
Using standard coordinate system

X component of speed is -cos(51)*14
Y component of speed is sin(51)*14

Answer 8

This is just ship 1

Answer 9

okay

Answer 10

try this with ship 2

Answer 11

so you will get speed of two ship

Answer 12

Multiply x and Y component of each ship seperately to find position
then just use distance formula

Answer 13

ok so
ship a is -97.49
ship b is 128.6
?

Answer 14

X position of Ship 1 at noon(12-10am)
-cos(51)*14 mile per hours * 2hour
-17.62

Y position of Ship 2 at noon
sin(51)*14*2=21.76

Answer 15

X position of Ship 2
-cos(56)*17*2=something

Y position of Ship 2
-sin(56)*17*2=something

Distance Formula
\[\sqrt(ship 1 (x) position - ship 2( x) position)^2+ship 1 (y) position - ship 2( y) position)^2)\]

Answer 16

X position of Ship 2
-cos(56)*17*2=-23.89

Y position of Ship 2
-sin(56)*17*2=17.73

Answer 17

so then I just plug those into the formula?

Answer 18

I got 19.01 for x position of ship 2

Answer 19

hmmm ok you're probably right

Answer 20

Yep

Answer 21

can you see the distance formula in full

Answer 22

no

Answer 23

it is basically
square root of (xposition of ship 1- xpos ship 2)^2 + (ypos ship 1-y pos ship 2)^2)

Answer 24

Is it physics or math?

Answer 25

math trig/pre calc

Answer 26

Were you able to get answer

Answer 27

?

Answer 28

ok I have to go back to the begining and replug in stuff cause i messed something up hold on

Answer 29

I will do the same thing

Answer 30

ok thanks

Answer 31

I got 45.73.....?

Answer 32

The answer is 37.19

Answer 33

I read that problem wrong it is 51 degree west of north ---- not north of west
so I have to switch sin to cos vice versa

Answer 34

okay I have no clue what i did then

Answer 35

Ship 1 position
X: - sin(51)*14*2 -- A
Y: cos(51)*14*2 --B

Ship 2 position
X: -sin(56)*17*2 -- C
Y: -cos(56)*17*2 --D

Answer 36

okay

Answer 37

sqrt((A-C)^2+(B-D)^2)

Answer 38

=37.19

Answer 39

ok thank you!