Question

Complete the square:
(5/7)x^2+(9/10)x+(-13/70)=0

Answer 1

ax^2+bx+c

Answer 2

do i multiply by 7/5 to get the coefficient of the squared term to be 1?

Answer 3

ax^2+2ab+b^2

Answer 4

Divide everything by 5/7

Answer 5

a=5/7
b=9/10

Answer 6

firstly divide everything by 5/7
x^2 + (63/50)x-(-13/50) = 0
(x+63/100)^2 - 3969/10000 - 13/50 = 0
(x+63/100)^2 = 6569/10000
x = - (63/100)+-sqrt(6569/10000)

Answer 7

then evaluate that .. that should hopefully be right (although i did it in my head, method is sound tho)

Answer 8

looking over my numbers...

Answer 9

got it! just went wrong on one of those huge fractions

Answer 10

you are amazing!

Answer 11

alternatively it is usually better instead of dividing it properly by 5/7, to put it outside a large bracket and leave it there, from start;
5/7[x^2+(63/65)x-(13/50) = 0

Answer 12

forgot end bracket .. but u get the gist

Answer 13

yes, great

Answer 14

ok glad i could help

Answer 15

I really appreciate it!