Question

the integral of 1/U^2 -16 is 1/*ln(u-4/u+4). i have determine whether it diverges or converges
intergal 4 to zero 1/u^2-16

Answer 1

over what interval?

Answer 2

4 to 0

Answer 3

is your integration right?

Answer 4

the integration is wrong is it not

Answer 5

let me check

Answer 6

srry i meant to write 1/8(ln u-4/u+4)

Answer 7

yh tht's better

Answer 8

for simplcity I will write down as
1/8 ln(u-4) - ln(u+4)

Answer 9

okay great

Answer 10

1/8(ln(R-4)-ln(R+4) - 1/8(ln(-4)-(ln(4))

Answer 11

as R approach 4
the first term become -infinity

Answer 12

its because it becomes ln (0/0)

Answer 13

ln(0) approach infinity

Answer 14

negative infinity

Answer 15

why

Answer 16

http://www.wolframalpha.com/input/?i=ln%280%29

Answer 17

k

Answer 18

ty

Answer 19

still problem?