Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (wolf):

3x(y)^(1/3) can someone help me implicitly differentiate this?

OpenStudy (anonymous):

3[x*y^(1/3)] 3[x*(1/3)y'y^(-2/3) + y^(1/3)] y'[x/y^(2/3)] + 3y^(1/3)

OpenStudy (wolf):

heres the rest of the problem

OpenStudy (wolf):

+3y'=0

OpenStudy (wolf):

whats the slope?

OpenStudy (wolf):

im just tryinging to make sure im doing this right

OpenStudy (bahrom7893):

y' = x*y^(1/3), are u given x and y

OpenStudy (wolf):

-3y^(1/3)/(x/(y^(2/3))+3)?

OpenStudy (wolf):

2,8

OpenStudy (wolf):

i left out a +3y in the original equation because i can do that easy lol

OpenStudy (bahrom7893):

wait a second can u post the whole equation? its not 3y'? its 3y?

OpenStudy (wolf):

3x(y)^(1/3)+3y

OpenStudy (wolf):

so the derivative is y'[x/y^(2/3)] + 3y^(1/3) + 3y'

OpenStudy (bahrom7893):

k workin on it

OpenStudy (wolf):

or thats what that other dude said it was atleast haha

OpenStudy (bahrom7893):

uploadin the solution

OpenStudy (bahrom7893):

can u please click on become a fan?! LOL I wanna get to 100 the answer is -12/7 btw

OpenStudy (bahrom7893):

http://i51.tinypic.com/2m68nyo.jpg

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!