square root of 8 over 8x^2
\[\sqrt(8/8x^2)\]
is this right?
no \[\sqrt{8}\div 8x ^{2}\]
okay thanks
sqrt(8) can be written as sqrt(4)* sqrt(2)
wait what i just want to know how to simplify it. i have teh answer in the book i just need help with the work. thats not the answer.
sqrt(4) =2 so 2sqrt(2)/8x^2 sqrt(2)/4x^2
my book says the answer should be 2sqrt(3)/3
are you sure you're looking at the right problem? because you're not gonna be able to get rid of the x^2 on the bottom
oh god your right. SORRY!! is sqrt(8)/ sqrt(6)
okay for that you do the same thing as above. break the 8 up into 4 * 2 and break the 6 up into 3 * 2 . now you have :\[{\sqrt{4}\sqrt{2}} \over \sqrt{2}\sqrt{3}\] now just divide the sqrt(2) out
\[{2 \over \sqrt{3}} \times {\sqrt{3} \over \sqrt{3}}\]
this will get rid of your radical on the bottom and change it to 3
okay i think i get it. your doing a different way then what im used to but it makes sense
how do you normally do it?
heres and example our teacher would break sqrt(8) to the sqrt(2x2x2) and sqrt(6) to sqrt(2x3)
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