I haveone more question. If the lenght of twolegs of a right triangle are: the square root of 3 and the square root of 6 , then the length of the hypotenuse is: ?
Have you seen the equation: a^2+b^2=c^2?
yes
Do you know what a and b represent?
is this the legs
Yep! So then the c represents the hypotenuse. So do you think you would know how to set up the problem?
not with square roots I don't
Well, the square roots (surprisingly) actually makes things a little easier. So we start with our original formula: a^2+b^2=c^2 And since you said a and b are the legs, we can substitute the measurements you gave: \[(\sqrt(3))^2+(\sqrt(6))^2=c^2\]
So technically if you square a square root it sort of cancels with one another. So \[(\sqrt(3))^2=3\]
and the same idea for \[(\sqrt(6))^2\] which would equal 6.
So where would you go from there?
would I go 3+6=c which would be c=9
Well technically it would be 3+6=9, so 9=c^2. So then you would take the sqaure root of both sides so you have c=?
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