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Mathematics 9 Online
OpenStudy (anonymous):

If u is t+1 and du is 1dt then what is the integral (u-1)u*u^(-1/2)?

OpenStudy (anonymous):

hey, how's it going?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Having issues with integral calculus and am way behind. I have to get caught up soon since the final is in two weeks. Basically I will probably be up until my girlfriend tells me to come to bed.

OpenStudy (anonymous):

subtle brag about girlfriend?

OpenStudy (anonymous):

no just truth...

OpenStudy (anonymous):

I'm not that shallow.

OpenStudy (anonymous):

haha, just kidding, do you mean the integral of ((u-1)(u)(u^(-1/2)))?

OpenStudy (anonymous):

yeah its via u-substitution. The original was kinda vague about where to start but I finally got past that with help from somebody here. dwobinkle or something like that

OpenStudy (anonymous):

so do you understand the part that has been done so far, or do you want to go over that?

OpenStudy (anonymous):

well if you like I can show you the original problem. I do get what has already been done because it was just the concept of trying factoring before anything else

OpenStudy (anonymous):

well from this point, you can simplify what you have by multiplying it out

OpenStudy (anonymous):

have you tried that?

OpenStudy (anonymous):

you can show me the original problem if you want just to make sure that the part you are showing me is correct

OpenStudy (anonymous):

Yeah but I am sadly failing at my algebra

OpenStudy (anonymous):

u(u-1) = u^2 - u

OpenStudy (anonymous):

so then you have (u^2 - u)(u^(-1/2))

OpenStudy (anonymous):

you still there?

OpenStudy (anonymous):

yeah just brushed my teeth...computer being weird online

OpenStudy (anonymous):

so do you follow so far? can you take it from here?

OpenStudy (anonymous):

...

OpenStudy (anonymous):

I got that far but I'm not quite sure...is it just regular power integrations now?

OpenStudy (anonymous):

got how far

OpenStudy (anonymous):

well the u^-1/2 should be multiplied into the parenthetical shouldn't it? Then we can just integrate?

OpenStudy (anonymous):

yes, sounds right, so what did you get as your answer?

OpenStudy (anonymous):

well that part leads to the integral of ((u^2/u^(1/2))-(u/u^(1/2))

OpenStudy (anonymous):

can you keep going?

OpenStudy (anonymous):

would the first term come out something like (2u^3/3u^1/2)?

OpenStudy (anonymous):

are you trying to integrate it straight from the last thing you typed?

OpenStudy (anonymous):

try using google chrome, that seems to be working better for me on this site

OpenStudy (anonymous):

Okay will do...Gonna go to bed thanks for the help.

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