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Mathematics 14 Online
OpenStudy (anonymous):

How do I find the integral of xy?

OpenStudy (anonymous):

what are you integrating with respect to?

OpenStudy (anonymous):

The original equation is y'-3xy=0 and I have to solve for y.

OpenStudy (anonymous):

This is how I would solve it.

OpenStudy (bahrom7893):

so: dy/dx - 3xy = 0 dy/dx = 3xy dy/y = 3xdx

OpenStudy (bahrom7893):

ln|y| = 3x^2/2 +C

OpenStudy (bahrom7893):

y = Ke^([3/2]x^2)

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