Question

Calculate the area between the region described by polar coordinates:
0 ≤ r ≤ sinθ
0 ≤ θ ≤ π

Answer 1

I think it is \[\pi/4\]

Answer 2

hey, how's it going?

Answer 3

Pretty good. I just tried working it out and got pi/2.
What I did was:
\[\int\limits_{0}^{\pi}\sin ^{2}\theta d \theta = \] \[1/2(x-\sin \theta \cos \theta)\] from pi to 0
Plugged pi and 0 into it and got pi/2

Answer 4

I think this is the way of proceeding, we get pi/4

\[\int\limits_{0}^{\pi} \int\limits_{0}^{\sin \phi}\rho d \rho d \phi\]