Question

(x^1/6y^1/3)^-18

Answer 1

so I will do numerator and denominator separately

Answer 2

okay thank you :0]

Answer 3

numerator --(x^1)^-18=x^-18

Answer 4

now what is this numerator go to?

Answer 5

denominator -- (6y^1/3)^-18
=(6^-18)*(y^-6)

Answer 6

put them together
(x^-18)/(6^-18)(y^-6)

Answer 7

okay break this down a bit. for the numerator where did you get the x^1?

Answer 8

wasn't that in the question?

Answer 9

no its x^1/6

Answer 10

no its x^1/6

Answer 11

oh, I misread the question, sorry

Answer 12

its okay it was just hiding is all. haha

Answer 13

(x^(1/6) * y^(1/3))^-18

x^-3 y^-6

Answer 14

I just multiplied the exponents

Answer 15

theres no multiplication sign between x and y

Answer 16

when there is nothing, it is assumed that they are being multiplied

Answer 17

oh okay. so for the exponents do you just make the 3 qnd 6 equal to -18?

Answer 18

When you have one exponent on another like this
\[(a^x)^y\]
You would multiply the exponents
x*y

Answer 19

can be rewritten as a^(x*y)

Answer 20

xy^1/18?

Answer 21

so in your case
(x^(1/6) * y^(1/3))^-18

Answer 22

nvm i got it x^-3 and y^-6 right?

Answer 23

you are right

Answer 24

is that as simpilified as im going to get?

Answer 25

Yes

Answer 26

alrighty thank you for helping me :0]

Answer 27

btw do you know that negative exponent could be written as positive if you put in denominator

Answer 28

no i didn't but that might be important right?

Answer 29

yes say you have something like
x^-a
you can rewrite it as
1/x^a

Answer 30

1/ over the equation

Answer 31

okay yeah i saw that in a video i was recently watching okay thanks a lot!! that will help towards my test. i really really apperciate everything. :0]

Answer 32

also
remember this
x^a * y^b=z^(a+b)
x^a/y^b= z^(a-b)

Answer 33

special cases??

Answer 34

no it is always the case

Trying solving this
x^2 * y^4

Answer 35

z^6?

Answer 36

Yes

Answer 37

I forgot to say this but x and y must be same

Answer 38

sorry my computer is running slow. in the cases you just showed me is that what your talking about?

Answer 39

yes

Answer 40

yes

Answer 41

2^3 * 2^2 = 8 * 4= 32

or 2^(3+2) = 2^5= 32

Answer 42

Will you test have log

Answer 43

okay for a the problem im working on now (x^1/3 /y^-2/3)^9 do i divide first?

Answer 44

log? like on the calculator?

Answer 45

since you do not know if x and y are same don't devide anything

Answer 46

Just do what we did on last problem

Answer 47

i did i got x^3/y^-6 but my book says the answer os x^3y^6

Answer 48

-2/3 * 9

Answer 49

i got -6 and i did the same for 1/3 and got 3

Answer 50

Both you and the book are right

Answer 51

1/a^-x = a^x

1/a^x = a^-x

Answer 52

hmmm? but i have the x^3 on top how can you fit a 1 by itself?

Answer 53

This is what you got
x^3/y^-6
using

1/a^-x = a^x

1/a^x = a^-x

x^3 * 1/y^-6
x^3 * y^6

Answer 54

oh okay that makes more sense.

Answer 55

1 * x^3 just x^3