Question

The average value of F(x)= -1/(x^2) on (1/2,1) is ?.

Answer 1

Integral from 1/2 to 1 of f(x)dx time 1/(b-a)

Answer 2

so it will be:
1 / (1-1/2) Integral from 1/2 to 1, etc..

Answer 3

so do i take the derevative or the anti ?

Answer 4

2 Integral from 1/2 to 1 of -1/(x^2) dx

Answer 5

oh ok so how i thought when i i need to go to an inegral i take the derevative

Answer 6

no u just integrate..

Answer 7

ok ty again

Answer 8

the answer im getting is -6 which is not a choice

Answer 9

-1 * 2 = -2

Answer 10

check the integral

Answer 11

sorry idk what im doing wrong...2(-1/(1/4))-2(-1/1)
so -8+2=-6 but that is clearly not right

Answer 12

Integral of -1/x^2 = Int [-1x^(-2) ] = -1 * x^(-2+1)/(-2+1) = x^(-1) from 1/2 to 1

Answer 13

1^(-1) - (1/2)^(-1) = 1 - 2 = -1

Answer 14

then 2*-1 = -2

Answer 15

haha tyvm it just clicked lol