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arch is shape like a arch can be parabola the arch can be appriximated by y =630-0.00635x2 both x and y distance in ft origin is the point on the ground below the arch apex find the x intercepts and how wide is the arch base
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Well, to find the x intercepts, we need to find x when y=0. \[0=630-.00635x^2\] Solving for x you should get, \[x^2=630\div.00635\] Because the arch is a parabola, we can use symmetry to find the length of the base. Remember when taking the square root of a number to include +/-. \[x=+/-\sqrt{99212.6}\] Bacause of symmetry, the distance is simply 2 times x, which should be 629.961 feet.
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