prove that 4^k > k^3
for k integer?
i mean k positive integer?
cantor it would work for non integers to... trying to think how you would prove it though
sorry..should have mentioned the conditions...k are positive integers...need to prove by mathematical induction..
thought so..... I was about to say induction
well when k = 0 the expression becomes 4^0>0^3 which becomes 1>0 which is true and as the value of k increases the first side of the expression increases at a much more rapid rate so that is why this is going to be true for all positive integers of k
check this page out http://answers.yahoo.com/question/index?qid=20101204110027AASBIgf it is similar to your problem and should walk you through the process, which is a long process
yes Nikko..that is true. but this is by intuition...proof by induction is bit complicated
give the base case, inductive hypothesis , and then prove by induction
thank you Nadeem...i'll go through the site
the only difference is that they had a parameter where \[n \ge5\]
give me a sec to work this out
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