Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

prove that 4^k > k^3

OpenStudy (anonymous):

for k integer?

OpenStudy (anonymous):

i mean k positive integer?

OpenStudy (anonymous):

cantor it would work for non integers to... trying to think how you would prove it though

OpenStudy (anonymous):

sorry..should have mentioned the conditions...k are positive integers...need to prove by mathematical induction..

OpenStudy (anonymous):

thought so..... I was about to say induction

OpenStudy (anonymous):

well when k = 0 the expression becomes 4^0>0^3 which becomes 1>0 which is true and as the value of k increases the first side of the expression increases at a much more rapid rate so that is why this is going to be true for all positive integers of k

OpenStudy (anonymous):

check this page out http://answers.yahoo.com/question/index?qid=20101204110027AASBIgf it is similar to your problem and should walk you through the process, which is a long process

OpenStudy (anonymous):

yes Nikko..that is true. but this is by intuition...proof by induction is bit complicated

OpenStudy (anonymous):

give the base case, inductive hypothesis , and then prove by induction

OpenStudy (anonymous):

thank you Nadeem...i'll go through the site

OpenStudy (anonymous):

the only difference is that they had a parameter where \[n \ge5\]

OpenStudy (anonymous):

give me a sec to work this out

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!