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describe the domain of the function f(x,y)=√(y-x2).
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\[\sqrt{y-x ^{2}}\]
What's under the radical cannot be negative. So, y - x^2 must be greater than or equal to 0. All points (x, y) that satisfy this requirement are in the domain of f(x, y).
So basically a good answer is that the domain of the function is: \[y \ge x^2\]
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