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please help me find the derivative of this one...\[y=e ^{-2x}(1+e ^{-2x})(-1 /\ 2)\]
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please help me with this one...i really need the answer right now
\[y=e ^{-2x}(1+e ^{-2x})^{-1/2}\] this is the problem...
Use product rule and chain rule \[dy/dx=e^{-4x}(1+e^{-2x})^{-3/2}-2e^{-2x}(1+e^{-2x})^{-1/2}\] after factoring you should get \[dy/dx=e^{-2x}(1+e^{-2x})^{-1/2}[e^{-2x}(1+e^{-2x})^{-1}+2]\]
I made a typing error it -2 not +2 \[dy/dx=e^{−2x}(1+e^{−2x})^{−1/2}[e^{−2x}(1+e^{−2x})^{-1}-2]\]
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