If the sound source is moving at sped v relative to the observer and if the speed of sound is V0, then the perceived frequency f is related to the actual frequency f0 as follows:
f = f0(v0/(v0(+/-)v))
We choose the minus sign if the source is moving toward the observer and the plus sign if it is moving away.
Suppose that a car drives at 100 ft/s past a woman standing on the shoulder of a highway, blowing it horn, which has a frequency of 500 Hz. Assume the speed of sound is 1130 ft./s.

Let A be the amplitude of the sound find the functions of the form
y = A sin wt
that model the perceived

Question

If the sound source is moving at sped v relative to the observer and if the speed of sound is V0, then the perceived frequency f is related to the actual frequency f0 as follows:
f = f0(v0/(v0(+/-)v))
We choose the minus sign if the source is moving toward the observer and the plus sign if it is moving away. 
Suppose that a car drives at 100 ft/s past a woman standing on the shoulder of a highway, blowing it horn, which has a frequency of 500 Hz. Assume the speed of sound is 1130 ft./s.

Let A be the amplitude of the sound find the functions of the form 
y = A sin wt 
that model the perceived

anonymous · Answer

sound of as the car approaches the woman and as it recedes

THANK YOU

radar · Answer

Actually the frequency would increase as source approaches the listener and decreases as sound source moves away from listener.

From your provided information the the frequency from the doppler effect is:
459 Hz when receding and 549 when approaching.

radar · Answer

This was derived from  f=f0(v0/v0+/-v)
Where f0=1130fps, V0=500Hz, and V=100fps