Use the equation given below to find f '' (π/3).
f (x) = sec(x)
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OpenStudy (anonymous):
first find f'(x) this is sec(x)tan(x). then find f''(x). you have to use the product rule to find the second derivative: take the derivative of sec(x) * tan(x) + the derivative of tan(x)*sec(x). once you have this you can just plug in pi/3 and solve.
OpenStudy (anonymous):
i got 48 but it showed my answer as wrong
OpenStudy (anonymous):
what did you get from the product rule?
OpenStudy (anonymous):
f'g+fg'
OpenStudy (anonymous):
I got sec(x)tan(x)tan(x) + sec(x)sec^2(x).
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OpenStudy (anonymous):
... do the product rule and tell me what you get.
OpenStudy (anonymous):
The is because Sec'(x) is sec(x)tan(x) and tan'(x) is sec^2(x)
OpenStudy (anonymous):
how do i find sec^2(pi/3)
OpenStudy (anonymous):
it is the same as sec(pi/3)sec(pi/3) so you should get 2*2
OpenStudy (anonymous):
i got 14
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OpenStudy (anonymous):
is that correct?
OpenStudy (anonymous):
hmmm i got 11. so sec(pi/3) is 2 and tan(pi/3) is (SQRT3)/2. So I got 2*(SQRT3)/2*(SQRT3)/2 + 2*2*2 this simplifies to 3 +8 which is 11
OpenStudy (anonymous):
WAIT thats wrong....
OpenStudy (anonymous):
it should be 3/2 + 8
OpenStudy (anonymous):
isnt tan pi/3 just SQRT 3?
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OpenStudy (anonymous):
so you would 2*sqrt 3*sqrt3+2*2*2
OpenStudy (anonymous):
oops yes you're right, sorry my trig isnt so great