Use the equation given below to find f '' (π/3). f (x) = sec(x)
first find f'(x) this is sec(x)tan(x). then find f''(x). you have to use the product rule to find the second derivative: take the derivative of sec(x) * tan(x) + the derivative of tan(x)*sec(x). once you have this you can just plug in pi/3 and solve.
i got 48 but it showed my answer as wrong
what did you get from the product rule?
f'g+fg'
I got sec(x)tan(x)tan(x) + sec(x)sec^2(x).
... do the product rule and tell me what you get.
The is because Sec'(x) is sec(x)tan(x) and tan'(x) is sec^2(x)
how do i find sec^2(pi/3)
it is the same as sec(pi/3)sec(pi/3) so you should get 2*2
i got 14
is that correct?
hmmm i got 11. so sec(pi/3) is 2 and tan(pi/3) is (SQRT3)/2. So I got 2*(SQRT3)/2*(SQRT3)/2 + 2*2*2 this simplifies to 3 +8 which is 11
WAIT thats wrong....
it should be 3/2 + 8
isnt tan pi/3 just SQRT 3?
so you would 2*sqrt 3*sqrt3+2*2*2
oops yes you're right, sorry my trig isnt so great
lol thats ok
so does make it 14?
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