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(x-3)(x-2)=24
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\[x^2-5x+6=24\] \[=x^2-5x-18=0\] \[D=(-5)^2-4(1)(-18)=25+72=97\] \[So x=(5+\sqrt{97})/2 or x=(5-\sqrt{97})/2\]
is there an easyer way to slove it
The easiest way is to use the scientific calculator to solve it.
i ment to put (x-3)(x+2)
No, that's not the way. You have to give that function to the form ax^2 + bx + c = 0
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then use your scientific calculator to solve it
(x-3)(x+2)
(x-3)(x+2) = 24 <=> x^2 - 5x - 18 = 0
so the eqn becomes x^2-x-30=0 so, (x-6)(x+5)=0 =x = -5 or x=6
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