Question

How do I get the derivative of ln(x^2)?

Answer 1

2/x

Answer 2

why though? isn't it the chain rule?

Answer 3

yes. d(ln u)/dx = 1/u(du/dx). So [1/(x^2)]*2x which simplifies to 2/x.

Answer 4

outer function: ln()
inner function: x^2 ...

d(outer function) = 1/x
d(inner function) = 2x

1/x * x^2 * 2x = 2x^2 ???

Answer 5

the d(outer function)= 1/(x^2) not 1/x.