find the equation of the tangent line to the graph of y=sqrt x/x+1 at point where x=1

Question

find the equation of the tangent line to the graph of y=sqrt x/x+1  at point where x=1

anonymous · Answer

Step 1.)Plug in x =1 in the equation and find the y-coordinate.

Step 2.)Take the derivative and evaluate it at x = 1. This will be your m in the next step.

Once you have these two things, use y=mx+b or $$y-y _{1}=m(x-x _{1})$$ to find the equation of the tangent line.

anonymous · Answer

im having a tough time finding the derivative for the equation, any way you could help?

anonymous · Answer

Could you re-write the equation properly? :D

anonymous · Answer

$$y=\sqrt{x}\div x+1$$

anonymous · Answer

$$y=\sqrt{x}/(x+1)$$ is that the equation?

anonymous · Answer

yes

anonymous · Answer

This will be the derivative.

$$(1-x)/(2(\sqrt(x)(x+1)^2)$$