Question

find the equation of the tangent line to the graph of y=sqrt x/x+1 at point where x=1

Answer 1

Step 1.)Plug in x =1 in the equation and find the y-coordinate.


Step 2.)Take the derivative and evaluate it at x = 1. This will be your m in the next step.

Once you have these two things, use y=mx+b or \[y-y _{1}=m(x-x _{1})\] to find the equation of the tangent line.

Answer 2

im having a tough time finding the derivative for the equation, any way you could help?

Answer 3

Could you re-write the equation properly? :D

Answer 4

\[y=\sqrt{x}\div x+1\]

Answer 5

\[y=\sqrt{x}/(x+1)\] is that the equation?

Answer 6

yes

Answer 7

This will be the derivative.

\[(1-x)/(2(\sqrt(x)(x+1)^2)\]