Question

how do find the derivative of r/(sqrt of r^2 +4)

Answer 1

use the derivative for division rule: f(x)/g(x) = f'(x)g(x)-f(x)g'(x)/g(x)^2

Answer 2

i tried that but i keep getting the wrong answer

Answer 3

= (sqrt of r^2 +4) - r(1/2)(2r)(r^2+4)^-1/2/r^2+4

Answer 4

=(r^2+4 - r^2) /(r^2+4)^3/2

Answer 5

=4 /(r^2+4)^3/2

Answer 6

o i see my mistake i put for the second part (r^2+4)^-3/2

Answer 7

the final answer is =4 /(r^2+4)^3/2

Answer 8

could you became my fan?

Answer 9

im still confused on the part (sqrt of r^2 +4) - r(1/2)(2r)(r^2+4)^-1/2/r^2+4

Answer 10

how did u get (r^2+4)^-1/2

Answer 11

i kept getting it to the power of -3/2

Answer 12

ok... when we derivative a function we always do this for example: the derivative of x^1/2 = 1/2(x)^(1/2-1) = 1/2(x)^-1/2

Answer 13

apply that for you example: the derivative of (r^2+4)^1/2 = (1/2)(2r)(r^2+4)^(1/2-1) = (r)(r^2+4)^(-1/2)

Answer 14

do you get it?

Answer 15

ooooooooooooo

Answer 16

hahaha ok i get it!! THANK YOU!!!

Answer 17

your welcome!