e^y + y cos(x) + (xe^y + sin(x) ) y' = 0
i need two methods to solve this. So far I know it is first order and nonlinear. It does not appear to be separable nor can i use an integrating factor because of e^y. I don't think it is homogeneous, again because of e^y.

Question

anonymous · Answer

it looks like i can make this a bernoulli type equation but how can i transform e^y to the form of y^n?

anonymous · Answer

Just from looking at it, I think it is an exact differential equation.

anonymous · Answer

ok i will give exact DE method a try. but since i need two methods and it looks like a bernoulli, what can i do about the e^y to make it like q(x)y^n?

anonymous · Answer

you can't it's not bernoullis

anonymous · Answer

alright, thanks so much for your help.