Question

(d/dx)[(x+8)/(x^2+x+2)]=

Answer 1

quotient again...

Answer 2

if we get a equition=f(x)/g(x)
the derivitive for the equition will be [f'(x)g(x)-f(x)g'(x)]/[g(x)]^2

Answer 3

hmmmyou sure? I thought it was g(prime)(x)f(x)-...first...

Answer 4

yep, I just check it after u asked

Answer 5

(d/dx)(T(x)/B(x)) = [B(x)T'(x)-T(x)B'(x)]/[B(x)]^2 is how I remember it.

T for top and B for bottom.

Answer 6

edwardhugh is right\[d/dx(x+8)/(x^2+x+2)=\]
\[[x^2+x+2-(x+8)(2x+9)]/(x^2+x+2)^2\]
\[=(-x^2-16x-6)/(x^2+x+2)^2\]\[=-(x^2+16x+6)/(x^2+x+2)^2\]
You can expand the denominator if you like, but this would be its simplified form