Question

how do you get (n+1) from (n+1)!/(n)! ?

Answer 1

I think it unravels like this [(n+1)(n)]/[n}, so it gives (n+1)

Answer 2

because you n's cancel out

Answer 3

*the

Answer 4

right!

Answer 5

does that help?

Answer 6

\[(n+1)!/n!= (n+1)(n)(n-1)(n-2)......./n(n-1)(n-2)......\]
sine the numerator and denominator both have (n)(n-1)(n-2)..../(n)(n-1)(n-2)..... they cancel out leaving n+1

Answer 7

yes, it makes a lot of sense. thank you!

Answer 8

that was rather simple. thanks guys