y''=8*y*3

I am supposed to solve this equation by multiplying both sides of the equation with y' , but I don't know what to do thereafter

The answer shall be: y=1/(C+-2x)
But I don't know how to get it, can anybody tell me the steps?

Question

y''=8*y*3

I am supposed to solve this equation by multiplying both sides of the equation with y' , but I don't know what to do thereafter

The answer shall be: y=1/(C+-2x) 
But I don't know how to get it, can anybody tell me the steps?

anonymous · Answer

I just don't quite see what to do just after having multiplied with y' , can you give me some hints?

anonymous · Answer

what isthe question, is it 8y^3?

anonymous · Answer

The question is the differential equation y''=8y^3

anonymous · Answer

You can solve using laplace transforms

anonymous · Answer

or actually nevermind you aren't given initial conditions

anonymous · Answer

ok, you just substitute v=y' then using chain rule y''=v*dv/dy. Sub everythign back into original and you get a separable equation with y's and v's

anonymous · Answer

ok, thank you very much