Question

(x^1/9*x^4/9)^18/15

Answer 1

is this your problem?
\[(x^\frac{1}{9}x^\frac{4}{9})^\frac{18}{15}\]

Answer 2

yea but you multiply the x's inside the parenthesis

Answer 3

i got x^2/3

Answer 4

\[(x^ \frac{1}{9}*x^\frac{4}{9})^\frac{18}{15}\] is the same thing as\[(x^ \frac{1}{9}x^\frac{4}{9})^\frac{18}{15}\]
\[(x^ \frac{1}{9}x^\frac{4}{9})^\frac{18}{15}= (x^\frac{5}{9})^\frac{18}{15}= x^\frac{90}{135}=x^\frac{2}{3}\]

Answer 5

yeah your right

Answer 6

that's exactly how i did it thanks

Answer 7

no prob

Answer 8

can you help me on another one.?

Answer 9

sure

Answer 10

3\[3\sqrt{2}+5\sqrt{2}\]

Answer 11

do i just add the 3 and 5?

Answer 12

yeah but do you know why you can do that?

Answer 13

because the square root is the same?

Answer 14

yeah, so you could factor out the square root of 2\[3\sqrt{2}+5\sqrt{2}=(3+5)\sqrt{2}=8\sqrt{2}\]

Answer 15

what happens if they aren't ... like this one:
\[6\sqrt{3}+10\sqrt{12}\]

Answer 16

think of how you can rewrite \[10 \sqrt{12}\]

Answer 17

don't know

Answer 18

so \[10 \sqrt{12}= 10 \sqrt{4*3}= 10\sqrt{4}\sqrt{3}= 20\sqrt{3}\]

Answer 19

so now you have \[6 \sqrt{3}+20 \sqrt{3}= (6+20)\sqrt{3}= 26\sqrt{3}\]

Answer 20

oooooooo okay now i get it so just get them to equal eachother

Answer 21

yeah, thats the idea..... but its not always that easy to see it

Answer 22

so like this one\[2\sqrt{5}-3\sqrt{20}\]

Answer 23

im going to try it hold up

Answer 24

oh my gosh.! i got it!

Answer 25

\[-4\sqrt{5}\]
that's my answer

Answer 26

nice.. thats right

Answer 27

there's another one its actually harder kinda confusing can you help me out on this one also please

Answer 28

sure

Answer 29

\[\sqrt[3]{3}+4\sqrt[3]{2}\]

Answer 30

yu there?

Answer 31

yeah, do you know the answer by any chance?

Answer 32

no but it's ok i 'll try my best 2mrw thanks n e way on the other ones huge help