Question

The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle?

If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?

a) 2x2 + 3x - 119 = 0
b) 3x2 + 3x - 119 = 0
c) 6x2 - 119 = 0

Answer 1

119 = A = WL; L=2W+3

119= W(2W+3)
119=2W^2 +3W
0= 2W^2 +3W -119 (a)

Answer 2

A= L * W
L=2x+3
W=x

(2x+3) * x= 119
2x^2 +3x =119
2x^2 +3x -119 = 0 ---->(a)